Answer:
Third option: Real and Irrational roots.
Step-by-step explanation:
For a Quadratic equation:
[tex]ax^2+bx+c=0[/tex]
The Discriminant can be found with this formula:
[tex]D=b^2-4ac[/tex]
Given the following Quadratic equation:
[tex]x^2 - 5x - 4 = 0[/tex]
You can identify that:
[tex]a=1\\b=-5\\c=-4[/tex]
Then, substituting these values into the formula for find the Discriminant, you get that this is:
[tex]D=(-5)^2-(4)(1)(-4)\\\\D=41[/tex]
Therefore, since the Discriminant is positive ([tex]D>0[/tex]) but it is not a perfect square, then the roots of the equation are Real and Irrational.