Question

find the distance between points p(8, -2) and q(-3, 4) to the nearest tenth

Answer 1

Use the formula:

$A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}$

We have:

$P(8;\ -2);\ Q(-3;\ 4)$

substitute

$|PQ|=\sqrt{(-3-8)^2+(4-(-2))^2}=\sqrt{(-11)^2+6^2}\\\\=\sqrt{121+36}=\sqrt{157}\approx12.5$