Question

if 50 milliliters (mL) of a 0.01 M HCl solution is required to neutralize exactly 25 milliliters (mL) of NaOH, what is the concentration of the base?
A. 0.01m
B. 0.02m
C. 0.0005m
D. 0.04m

Answer 1

NaOH + HCl ----> NaCl + H2O

From reaction number of mole NaOH should be equal number of mole HCl.
n=MV
n- number of mole,
M - molarity,
V- volume.
M(NaOH)*V(NaOH) = M(HCl)*V(HCl)
M(NaOH)*25 ml = 0.01M*50 ml
V(NaOH) = 0.01*50/25=0.02 M
Answer B. 0.02 M

Answer 2

0.02 M is the concentration of the base if 50 milliliters (mL) of a 0.01 M HCl solution is required to neutralize exactly 25 milliliters (mL) of NaOH.

Define molarity of a solution.

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

$NaOH + HCl$ ----> $NaCl + H_2O$

From reaction number of mole NaOH should be equal number of mole HCl.

n=MV

n- number of mole,

M - molarity,

V- volume.

M(NaOH) X V(NaOH) = M(HCl) X V(HCl)

M(NaOH) X 25 ml = 0.01M X 50 ml

0.02 M

Hence, 0.02 M is the concentration of the base if 50 milliliters (mL) of a 0.01 M HCl solution is required to neutralize exactly 25 milliliters (mL) of NaOH.

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