Question

what is the molarity of a KOH solution if it requires 20 milliliters of 2.0m HCl to exactly neutralize 20 milliliters of the KOH solution?

A. 1.0m
B. 2.0m
C. 10m
D. 20m

Answer 1

KOH + HCl     ------->    KCl +H2O

From the reaction we can see that
number of moles KOH = number of mole HCl
M - molarity, V - vloume, n -number of moles

n=MV
M(KOH)*V(KOH) = M(HCl)*V(HCl)
M(KOH)*20 ml = 2.0*V(HCl)*20 ml
M(KOH) = 2*20/20=2
Answer B. 2.0 M

Answer 2

The molarity of a KOH solution if it requires 20mL of 2.0M HCl to exactly neutralize 20mL of the KOH solution is 2M.

How do we calculate molarity?

Molarity of the solution in the given condition will be calculated by using the below formula:
M₁V₁ = M₂V₂, where

M₁ = molarity of KOH solution = ?

V₁ = volume of KOH solution = 20 mL

M₂ = molarity of HCl solution = 2 M

V₂ = volume of HCl solution = 20 mL

On putting these values on the aboive equation, we get

M₁ = (2)(20) / (20)

M₁ = 2 M

Hence required molarity of KOH solution is 2M.

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