Question

The following balanced equation shows the decomposition of ammonia (NH3) into nitrogen (N2) and hydrogen (H2). 2NH3 → N2 + 3H2 A quantity of NH3 decomposes to produce 0.0351 mol N2. How many moles of H2 are produced? 0.0351 mol H2 0.0117 mol H2 0.105 mol H2

Answer 1

The decomposition of ammonia is characterized by the following decomposition equation:
                                  2NH₃   →   N₂   +   3H₂   

The mole ratio of N₂  :  H₂  is  1  :  3

    If the number of moles of N₂  =  0.0351 mol
    Then the number of moles of H₂  =  0.0351 mol  × 3
                                                         = 0.1053 mol

The number of moles of hydrogen gas produced when 0.0351 mol of Nitrogen gas is produced after the decomposition of Ammonia is  0.105 mol (OPTION 3).

Answer 2

0.105 mol (OPTION 3).