Question

We are interested in the dimensions of a certain square. A rectangle has length triple the sides of this square and width two units less than the side of this square. Which equation describes this situation if the two areas are equal?

Answer 1

If we assume that the length of the sides of the square are x, then the resulting area will then be:

$A=l*w=x*x= x^{2}$

Then we have the rectangle, whose length triples the square. This will be represented by: 3x

And the width of this rectangle is 2 units less than the side of the square, so it is represented as: (x - 2)

The area of the rectangle can then be represented by:

$A=l*w=3x(x-2)$

The questions says that the two areas are equal, so set the areas equal to each other, and you get:

$x^{2} =3x(x-2)$ or C