Respuesta :
[tex] \frac{18x^5 +6x^4 - 12x^3}{6x^2} = \frac{(6x^2)(3x^3 +x^2 - 2x)}{6x^2} = 3x^3 +x^2 - 2x[/tex]
The answer is: " 3x³ + x² − 2x " .
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Explanation:
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Take the first expression; or the "numerator" ;
and "factor out" a: " 6x² " :
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[tex] \frac{18x^5+6x^4-12x^3}{6 x^{2} } = \frac{6x^2(3x^3+x^2-2x)}{6x^2} [/tex] ;
→ Both " 6x² " values "cancel out to 1" ;
→ since: " { 6x² / 6x² = 1 } " ;
And we have: " 3x³ + x² − 2x " .
________________________________________________________
________________________________________________________
Explanation:
_________________________________________________________
Take the first expression; or the "numerator" ;
and "factor out" a: " 6x² " :
___________________________________________________________
[tex] \frac{18x^5+6x^4-12x^3}{6 x^{2} } = \frac{6x^2(3x^3+x^2-2x)}{6x^2} [/tex] ;
→ Both " 6x² " values "cancel out to 1" ;
→ since: " { 6x² / 6x² = 1 } " ;
And we have: " 3x³ + x² − 2x " .
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