Question

How many solutions does this equation have? a+3+2a=-1+3a+4

Answer 1

Let's start by cleaning up this equation to make it easier to read by putting all the variables on one side and everything else on the other side using subtraction and addition. Then simplify.
1) Original equation 
a + 3 + 2a = -1 + 3a + 4

2) Subtract 3 from both sides
a + 2a = -3 - 1 + 3a + 4

3) Subtract 3a from both sides
a + 2a - 3a = -3 - 1 + 4

4) Simplify
3a - 3a = -4 + 4
0 = 0

Since 0 = 0 is always true, this equation as an unlimited number of solutions. No matter what you put in for the variable a, it will all cancel out, and you'll get 0 = 0!

------

Answer: Infinite number of solutions

Answer 2

We want to see how many solutions does the given equation has. By direct calculation, we will see that the equation has infinite solutions.

So the given equation is:

a + 3 + 2a = -1 + 3a + 4

Let's solve this, first we move all the terms with a to the left side and the terms without a to the right side:

a + 2a - 3a = -1 + 4 - 3

Now we simplify:

3a - 3a = (-1 - 3) + 4

0 = 0

So this is an identity, which means that the variable "a" can take any value and the equation will always be true (because the equation actually does not depend on a).

Thus we have infinite solutions of the given equation.

If you want to learn more, you can read:

https://brainly.com/question/11246392