Two companies modeled their profits for one year.

Company A used the function P(t)=1.8(1.4)^t to represent its monthly profit, P(t), in hundreds of dollars, after t months, where 0 < t ≤ 12.

Company B used the data in the table to write a linear model to represent its monthly profits.

Which statement describes the relationship between the profits, predicted be the models, of the two companies?

Two companies modeled their profits for one year Company A used the function Pt1814t to represent its monthly profit Pt in hundreds of dollars after t months wh class=

Respuesta :

we know the equation for company A is P(t) = 1.8(1.4)ᵗ.

and what we know about company B is that their equation is linear, and we also have 3 months in a table of values, and we can simply use two points from there to get the equation of company B, let's do so using (3,5) and (7, 25),

[tex]\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ 3 &,& 5~) % (c,d) &&(~ 7 &,& 25~) \end{array} \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{25-5}{7-3}\implies \cfrac{20}{4}\implies 5 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-5=5(x-3) \\\\\\ y-5=5x-15\implies y=5x-10\implies p(t)=5t-10[/tex]

now, the end of the year will be at the twelfth month, namely t = 12, and the four month well we know that t = 4.

how did each one fare?

[tex]\bf \stackrel{\textit{at the 4th month}}{\stackrel{\textit{company A}}{P(4)=6.91488}\qquad \qquad \stackrel{\textit{company B}}{p(4)=10}} \\\\\\ \stackrel{\textit{at the end of the year}}{\stackrel{\textit{company A}}{P(12)\approx 102.04904}\qquad \qquad \stackrel{\textit{company B}}{p(12)=70}}[/tex]

so, notice, on the fourth month B did better than A, but at the end of the year, A ended up better off than B.
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Company B follows linear profit function while company A follows exponential profit function. Company B has more profit after 4 months while company A has more monthly profit after year-end. Option A is correct.

Given information:

Company A earns monthly profit based on the profit function, [tex]P(t)=1.8(1.4)^t[/tex] where t is the number of months.

Company B earns profit based on a linear function. The data in the below table shows the profit after each month:

Month 3 4 7

Profit 5 10 25

Now, the profit earned by company A after 4 months will be,

[tex]P(4)=1.8(1.4)^4\\P(4)=1.8\times 3.8416\\P(4)=6.915[/tex]

Also, the profit earned after a year will be,

[tex]P(12)=1.8(1.4)^{12}\\P(4)=102.04[/tex]

Now, the linear function which represents the profit of company B is,

[tex]P-5=\dfrac{10-5}{4-3}(t-3)\\P-5=5t-15\\P=5t-10[/tex]

So, the profit earned after 4 months and 1 year (by company B) will be,

[tex]P(4)=5\times 4-10=10\\P(12)=5\times 12-10=50[/tex]

Now, comparing the profit of companies A and B:

After 4 months, company B has more monthly profit which is 10 hundred dollars or 1 thousand dollars. After the year-end, company A earns more monthly profit as it is 102.04 hundred dollars. This is because company A follows an exponential function to predict the profit while company B uses a linear profit function.

Therefore, option A should be correct.

For more details, refer to the link:

https://brainly.com/question/14628115

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