Seudónimo Seudónimo
  • 27-05-2018
  • Mathematics
contestada

Solve 3n^2+17n+10=0
a. n = -2/3 or n = -5
b. n = -2/3 or n = 3
c. n = 0 or n = 5
d. n = -5 or n = 3

Respuesta :

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gmany gmany
  • 27-05-2018
[tex]3n^2+17n+10=0\\\\3n^2+15n+2n+10=0\\\\3n(n+5)+2(n+5)=0\\\\(n+5)(3n+2)=0\iff n+5=0\ \vee\ 3n+2=0\\\\n=-5\ \vee\ n=-\dfrac{2}{3}[/tex]

[tex]Answer:\ a.\ n=-\dfrac{2}{3}\ or\ n=-5[/tex]

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