Question

f(x) = x^2 -­ 16 and g(x) = x+4. Find f/g and its domain

Answer 1

$f(x)=x^2-16\\\\g(x)=x+4\\\\\dfrac{f}{g}(x)=\dfrac{x^2-16}{x+4}\\\\The\ domain:\ x+4\neq0\to x\neq-4\\\\\dfrac{f}{g}(x)=\dfrac{(x-4)(x+4)}{x+4}=x-4$

$Used:\ a^2-b^2=(a-b)(a+b)$