Respuesta :
Let first alloy contains x pounds of silver, which is 50% of full weight, then the weight of first alloy is 2x.
The second alloy has weight 35-2x pounds and contains 15% silver, then weight of silver in this alloy is (35-2x)*0.15 pounds.
35 pounds of mixed alloy contains 38% silver, that is 35*0.38=13.3 pounds.
If you add the weights of silver from two alloys you obtain the weight 13.3 pounds (the weight of silver in mixed alloy).x+(35-2x)*0.15=13.3x+5.25-0.3x=13.3
0.7x=13.3-5.25=8.05
x=8.05÷0.7=11.5 pounds (silver content in the first alloy) and 2x=23 pounds is the weight of first alloy.
35-23=12 pounds is the weight of second alloy and 12*0.15=1.8 pounds (silver content in the second alloy).
The second alloy has weight 35-2x pounds and contains 15% silver, then weight of silver in this alloy is (35-2x)*0.15 pounds.
35 pounds of mixed alloy contains 38% silver, that is 35*0.38=13.3 pounds.
If you add the weights of silver from two alloys you obtain the weight 13.3 pounds (the weight of silver in mixed alloy).x+(35-2x)*0.15=13.3x+5.25-0.3x=13.3
0.7x=13.3-5.25=8.05
x=8.05÷0.7=11.5 pounds (silver content in the first alloy) and 2x=23 pounds is the weight of first alloy.
35-23=12 pounds is the weight of second alloy and 12*0.15=1.8 pounds (silver content in the second alloy).
By solving linear equation we got that if first alloy contains x pounds of 50% silver. it is mixed with a second alloy containing 15% silver to make 35 pounds of an alloy containing 38% silver then value of x is 11.5
What is linear equation ?
A equation of degree one is known as linear equation.
Here given that A first alloy contains x pounds of 50% silver. it is mixed with a second alloy containing 15% silver to make 35 pounds of an alloy containing 38% silver
So weight of first alloy =2x
weight of second alloy =35-2x
weight of silver in second alloy = (35-2x)(0.15)
35 pounds of mixed alloy contains 38% silver, that is 35(0.38)=13.3 pounds.
Now we can write it as
[tex]x+(35-2x)\times0.15=13.3x+5.25-0.3x=13.3\\\\0.7x=13.3-5.25=8.05[/tex]
[tex]x=8.05/0.7=11.5[/tex]
now
weight of first alloy =2x = 23
weight of second alloy =35-2x =35-23=12
weight of silver in second alloy = (35-2x)(0.15)=12(0.15)= 1.8
By solving linear equation we got that if first alloy contains x pounds of 50% silver. it is mixed with a second alloy containing 15% silver to make 35 pounds of an alloy containing 38% silver then value of x is 11.5
To learn more about linear equation visit : brainly.com/question/14323743
