Respuesta :
To complete this reaction a helium particle must be added.
²²²Rn₈₆ --> ²¹⁸Po₈₄ + ⁴He₂
This reaction is an example of α decay. In this decay an unstable atom becomes stable by emitting αparticle that is a nuclei a helium so its mass is reduced by 4 units and its atomic number is reduced by 2 units. And the atom becomes stable .
On going from ²²²Rn₈₆ to ²¹⁸Po₈₄, we can see that there is difference in mass number of 4 and in atomic number of 2. So this is clear that a helium nuclei is emitted.
