Question

please help asap 50 pts

Answer 1

If you factor the expression by grouping you should get (3g - 5) (2g +7)

Steps:
1. Factor 11 out of 11g
6g^2 + 11 (g) - 35

2. Rewrite 11 as -10 plus 21
6g^2 + (-10 + 21) g - 35

3. Apply the distributive property
6g^2 + (-10g + 21g) - 35

4. Remove parentheses
6g^2 - 10g + 21g - 35

5. Group the first two and the last two terms
(6g^2 - 10g) + (21g - 35)

6. Factor out the greatest common factor from each group
2g (3g - 5) + 7 (3g - 5)

7. Factor out the greatest common factor, 3g - 5
(3g - 5) (2g + 7)


Therefore the answer is A

Answer 2

$6g^2+11g-35=6g^2+21g-10g-35=3g(2g+7)-5(2g+7)=(2g+7)(3g-5)$
Answer: A. (3g - 5)(2g + 7)