Respuesta :

kanest
Use the process of elimination.

There is a positive b value and a negative c value, which means that there is a negative factor and positive factor. This eliminates A and C.

Multiply out the factors in B and D:

B
(6d - 1)(2d + 1)
6d * 2d = 12d^2
6d * 1 = 6d
2d * -1 = -2d

12d^2 + 4d - 1

D
(6d + 1)(2d - 1)
6d * 2d = 12d^2
6d * -1 = -6d
2d * 1 = 2d


12d^2 - 4d - 1


The answer is B.
gmany
[tex]12d^2+4d-1=12d^2+6d-2d-1=6d(2d+1)-1(2d+1)=(2d+1)(6d-1)[/tex]

Answer: B. (6d - 1)(2d + 1)

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