This is the concept of equations of graphs; We are required to calculate for the equation if the line that is perpendicular to the line 4x-3y=-8 and passes through the point (3,-2). Here we proceed as follows;4x-3y=-8 can be written in the form y=mx+c as follows;-3y=-4x-8thus;y=4/3x+8/3The slope of the line perpendicular to this is -3/4. Thus using p[oint (3,-2) the equation will be as follows;-3/4=(y--2)/(x-3)-3/4(x-3)=y+2y+2=-3/4(x-3)y+2=-3/4x+9/4thus;y=-3/4x+1/4the answer is:y=-3/4x+1/4
