Question

In rectangle ABCD, the angle bisector of ∠A intersects side
DC
at point M and the angle bisector of ∠C intersects side
AB
at point N. The length of
CM
is equal to the length of
AM
and it is 6 in longer than the length of
DM
. Find the perimeter of quadrilateral ANCM.

Answer 1

48+24 square two
DM=AD (45, 45,90)
Use pythagorean theorum to find x
(x-6)^2+(x-6)^2=x^2
you get
(12+6 (root)2)
since all the sides are the same you multiply that by four

Answer 2

Answer:

P=48+24$\sqrt{2}$ in.

Step-by-step explanation: