20-05-2018
Mathematics

contestada

A straight line with x-intercept -6 is parallel to the line 5x+3y=15. Find the y-intercept of that line

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juliadicaprio juliadicaprio

20-05-2018

Subtract the 5x to move it to the other side to get 3y = -5x + 15

Then, divide by 3 to get y by itself to get
y = -(5/3)x + 5

The y-intercept of the line 5x + 3y = 15 would be 5. Hope this helps you!

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-10a ^5/-40a ^6+50a^5

Five solutions for the linear equation 3x-5y=15