Respuesta :
Theodore sits on a stand with his mouth 5 feet 6 inches above the ground:
x1=0
y1=5 feet 6 inches=(5 feet)(12 inches / 1 foot) 6 inches=60 inches 6 inches
y1=66 inches
(x1, y1)=(0, 66)
When standing directly in front of the frog, each person is exactly one foot from Theodore:
x2=1 foot→x2=12 inches
If the tallest person's nose that Theodore can touch has a nose that is exactly 6 feet 4 inches off the ground:
y2=6 feet 4 inches=(6 feet)(12 inches / 1 foot) 4 inches=72 inches 4 inches
y2=76 inches
(x2, y2)=(12, 76)
a. What would be the height of the nose of the shortest person that Theodore could lick?
y3=?
y3=y1-dy
dy=y2-y1=76 inches-66 inches→dy=10 inches
y3=y1-dy=66 inches-10 inches=56 inches=48 inches + 8 inches
y3= (48 inches) ( 1 foot / 12 inches) 8 inches
y3=4 feet 8 inches
Answer: The height of the nose of the shortest person that Theodore could lick would be 4 feet 8 inches
b. What is the maximum distance that theodore can stick his tongue out?
d=?
d=sqrt[ (x2-x1)^2+(y2-y1)^2 ]
d=sqrt[ (12 inches - 0)^2+(76 inches-66 inches)^2 ]
d=sqrt[ (12 inches)^2+(10 inches)^2]
d=sqrt(144 inches^2+100 inches^2)
d=sqrt(244 inches^2)
d=sqrt(4x61 inches^2)
d=sqrt(4) sqrt(61) sqrt(inches^2)
d=2 sqrt(61) inches
d=2(7.81) inches
d=15.62 inches
Answer: The maximum distance that theodore can stick his tongue out is
2 sqrt(61) inches = 15.62 inches
x1=0
y1=5 feet 6 inches=(5 feet)(12 inches / 1 foot) 6 inches=60 inches 6 inches
y1=66 inches
(x1, y1)=(0, 66)
When standing directly in front of the frog, each person is exactly one foot from Theodore:
x2=1 foot→x2=12 inches
If the tallest person's nose that Theodore can touch has a nose that is exactly 6 feet 4 inches off the ground:
y2=6 feet 4 inches=(6 feet)(12 inches / 1 foot) 4 inches=72 inches 4 inches
y2=76 inches
(x2, y2)=(12, 76)
a. What would be the height of the nose of the shortest person that Theodore could lick?
y3=?
y3=y1-dy
dy=y2-y1=76 inches-66 inches→dy=10 inches
y3=y1-dy=66 inches-10 inches=56 inches=48 inches + 8 inches
y3= (48 inches) ( 1 foot / 12 inches) 8 inches
y3=4 feet 8 inches
Answer: The height of the nose of the shortest person that Theodore could lick would be 4 feet 8 inches
b. What is the maximum distance that theodore can stick his tongue out?
d=?
d=sqrt[ (x2-x1)^2+(y2-y1)^2 ]
d=sqrt[ (12 inches - 0)^2+(76 inches-66 inches)^2 ]
d=sqrt[ (12 inches)^2+(10 inches)^2]
d=sqrt(144 inches^2+100 inches^2)
d=sqrt(244 inches^2)
d=sqrt(4x61 inches^2)
d=sqrt(4) sqrt(61) sqrt(inches^2)
d=2 sqrt(61) inches
d=2(7.81) inches
d=15.62 inches
Answer: The maximum distance that theodore can stick his tongue out is
2 sqrt(61) inches = 15.62 inches
