Missy's kinetic energy just before hitting the bucket of water is given by
[tex]K= \frac{1}{2}mv^2 [/tex]
where m is Missy's mass and v her speed. Since we know the value of the kinetic energy, K=15000 J and the mass, m=50 kg, we can find Missy's speed before hitting the water bucket:
[tex]v= \sqrt{ \frac{2K}{m} } = \sqrt{ \frac{2 \cdot 15000 J}{50 kg} } =24.5 m/s[/tex]