Respuesta :
The rms potential difference of an ac generator is given by:
[tex]V_{rms} = \frac{V_0}{ \sqrt{2} } [/tex]
where [tex]V_0[/tex] is the maximum value of the voltage.
For the ac generator in our problem, [tex]V_0=215 V[/tex], therefore the rms value of the potential difference is
[tex]V_{rms} = \frac{V_0}{ \sqrt{2} } = \frac{215 V}{ \sqrt{2} }=152 V [/tex]
[tex]V_{rms} = \frac{V_0}{ \sqrt{2} } [/tex]
where [tex]V_0[/tex] is the maximum value of the voltage.
For the ac generator in our problem, [tex]V_0=215 V[/tex], therefore the rms value of the potential difference is
[tex]V_{rms} = \frac{V_0}{ \sqrt{2} } = \frac{215 V}{ \sqrt{2} }=152 V [/tex]
The rms potential difference is found by the ratio of maximum output emf to the square root of 2. The value of rms potential difference will be 152 V.
What is an AC generator?
A machine that transforms mechanical energy into electrical energy is known as an AC generator.
The rms potential difference is given by;
[tex]\rm V_{rms}=\frac{v_0}{\sqrt{2} } \\\\ \rm V_{rms}=\frac{215 V}{\sqrt{2} } \\\\ \rm V_{rms}=152 V[/tex]
Hence the rms potential difference will be 152V
To learn more about the AC generator refer to the link;
https://brainly.com/question/10093221