Greenrune113
Greenrune113
17-05-2018
Mathematics
contestada
QF Q2.) Solve the triangle
Respuesta :
EEPJR
EEPJR
17-05-2018
60°
11
12
see photo for soln
Answer Link
Asdfjkadfjkakjf
Asdfjkadfjkakjf
19-05-2018
C=180-A-B=180-67-53=60deg.
by sine rule
b/sinB=a/sinA
b=a/sinA*sinB
=13/sin(67)*sin(53)
= 11.28
c/sinC=a/sinA
c=a/sinA*sinC
=13/sin(67)*sin(60)
= 12.23
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