Question

if a plant uses 44 grams of carbon dioxide and 18 grams of water to produce 32 grams of oxygen, how many grams of glucose are produced for the plant to use

6H2O + 6CO2 --> C6H12O6 + 6O2

Answer 1

the balanced equation for the reaction is as follows 
6H₂O + 6CO₂ ---> C₆H₁₂O₆ + 6O₂

number of moles of CO₂ used - 44 g / 44 g/mol = 1 mol
number of moles of H₂O used - 18 g / 18 g/mol = 1 mol
stoichiometry of CO₂ to H₂O is 6:6 = 1:1
1 mol of CO₂ present and 1 mol of H₂O present therefore they are both fully used up in the reaction of molar ratio 1:1
number of moles of O₂ formed - 32 g/ 32 g/mol = 1 mol

stoichiometry of CO₂:H₂O:C₆H₁₂O₆:O₂ is 6:6:1:6
1 mol of CO₂ has reacted with 1 mol of H₂O to form 1 mol of O₂ and x mol of C₆H₁₂O₆

the number of C₆H₁₂O₆ moles is 1/6th of CO₂ moles used up
since CO₂ moles - 1 mol 
therefore C₆H₁₂O₆ moles formed - 1/6 mol = 0.167 mol
mass of glucose formed - 0.167 g x 180 g/mol = 30 g 
therefore 30 g of glucose is formed 

Answer 2

The study of chemicals is called chemistry. The breakdown of the compound is called decomposition reaction.

The correct answer to the question is 50g.

Combination reaction?

• The formation of a new compound by joining the different elements is called a combination reaction.

The balanced equation for the reaction is as follows

$6H_2O + 6CO_2 ---> C_6H_{12}O_6 + 6O_2$

The solution is as follows:-

• Number of moles of CO₂ used - $\frac{44 }{ 44 } = 1 mol$
• Number of moles of H₂O used - $\frac{18 }{18} = 1 mol$
• Stoichiometry of CO₂ to H₂O is 6:6 = 1:1

1 mole of CO₂ present and 1 mole of H₂O present therefore they are both fully used up in the reaction of molar ratio 1:1

Number of moles of O₂ formed - $\frac{32}{32} =1 mole$

stoichiometry of $CO_2:H_2O:C_6H_{12}O_6:O_2$ is 6:6:1:6

1 mol of CO₂ has reacted with 1 mol of H₂O to form 1 mol of O₂ and x mol of C₆H₁₂O₆

The number of C₆H₁₂O₆ moles is 1/6th of CO₂ moles used up since CO₂ moles - 1 mol

Therefore C₆H₁₂O₆ moles formed - 1/6 mol = 0.167 mol

Hence, the mass of glucose formed -$0.167 g * 180 g/mol = 30$ g

Hence, the correct answer is 30g.

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