Question

Triangle fgh is inscribed in circle o the length of radius oh is 6 and fh is congruent to og. what is the area of the sector formed by angle foh

Answer 1

Given :
Triangle fgh is inscribed in circle o

oh = 6 = radius of the circle 
∵ fh is congruent to og

∴ fh = og = radius og the circle = 6

∵ of = radius of the circle = 6

∴ oh = fh = of = radius of the circle = 6

∴ Δ foh is Equilateral Triangle

∴∠ foh = 60° ⇒⇒⇒ property of the equilateral Triangle

∵ total area of the circle = π r²  and total central angle of the circle = 360°
∴ Area of sector foh = (60°/360°) * π r²
∴ Area of sector foh = (60°/360°) * π * 6² ≈ 18.85

The answer is:

the area of the sector formed by angle foh  = 18.85

Answer 2

The area of the sector formed by angle FOH is known as  6 pi. Check more about the question below.

What is the Triangle about?

Note that FH ≅ OG

Therefore, we say that Angle FOH is known to be a equilateral triangle.

So we can say that FOH = 60°

So angle FOH = 60/360 π

So therefore the answer will be 6π  or write as 6 pi.

Learn more about congruent from

https://brainly.com/question/2938476

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