Question

Silver (ag) has a molar mass of 107.8682 g, nitrogen has a molar mass of 14.0067 g, and oxygen has a molar mass of 15.9994 g. what is the molar mass of silver nitrate, agno3?

Answer 1

AgNO3=
$(ag + n + o3) = \\ (107.8682) + (14.0067) + (15.9994 \times 3) \\ = 169.8731g \: per \: mole$

Answer 2

Answer : The molar mass of silver nitrate $(AgNO_3)$ is, 169.87 g

Explanation :

Molar mass : It is defined as mass of 1 mole of a substance.

Given:

Molar mass of Sliver (Ag) = 107.8682 g

Molar mass of nitrogen (N) = 14.0067 g

Molar mass of oxygen (O) = 15.9994 g

Now we have to calculate the molar mass of silver nitrate $(AgNO_3)$

Molar mass of silver nitrate $(AgNO_3)$ = Molar mass of Sliver (Ag) + Molar mass of nitrogen (N) + (3 × Molar mass of oxygen (O))

Molar mass of silver nitrate $(AgNO_3)$ = 107.8682 g + 14.0067 g + 3(15.9994 g)

Molar mass of silver nitrate $(AgNO_3)$ = 169.87 g

Therefore, the molar mass of silver nitrate $(AgNO_3)$ is, 169.87 g