Respuesta :
The first part of the question is 3,100 V.
The second part of the question is 200 V.
The second part of the question is 200 V.
Electric potential due to a point charge is given by
[tex]V = \frac{kQ}{r}[/tex]
here we know that
Q = charge
r = distance from the charge
[tex]V = \frac{9*10^9* 2.2* 10^{-6}}{6.3}[/tex]
[tex]V = 3142.8 Volts[/tex]
now again by the same equation
[tex]V = \frac{kQ}{r}[/tex]
[tex]V = \frac{9*10^9* 2.2* 10^{-6}}{99}[/tex]
[tex]V = 200 Volts[/tex]