Question

What is the solution to the equation below?3log_4x=log_43 2+log_4 2
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Answer 1

$\frac{3\log _4\left(x\right)}{3}=\frac{\log _4\left(32\right)}{3}+\frac{\log _4\left(2\right)}{3}$
Simplify
$\log _4\left(x\right)=\frac{\log _4\left(32\right)+\log _4\left(2\right)}{3}$
$\log _4\left(x\right)=1$
Apply log rule
$\log _4\left(x\right)=\log _4\left(4\right)$
Answer:
$x=4$