We have been given a quadratic equation [tex]x^{2}-12x=61[/tex] and we have to complete the square of the given equation.
We know that a perfect square is in form of [tex]a^{2}+2ab+b^{2}[/tex]. Comparing the given equation we can see that [tex]a^{2}[/tex] in case is equal to [tex]x^{2}[/tex] and 2ab equals to -12x.
Now we have to figure what [tex]b^{2}[/tex] we should add to our equation to get a perfect square.
Since we know we can complete the square by taking half of coefficient of x term and squaring it.
Coefficient of x in our equation is 12 so to get [tex]b^{2}[/tex] of our equation we have to divide it by 2. After dividing by 2 we will get 6 and now we will take square of 6.
[tex]6^{2}=36[/tex]
Now we have to add 36 to both sides of our equation to hold our original equation true.
[tex]x^{2}-12x+36=61+36\\
x^{2}-12x+36=97[/tex]
So we have to fill in the given space 36 to left hand side of equation and 97 to right hand side of equation.