Concave lens is a diverging lens and it diverge all light that comes into it.
Now when light come to the lens it forms an image using the formula
[tex]\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}[/tex]
here when we put all the value since focal length of the concave lens is taken to be negative so its image position will be di
now if we calculate the magnification of the image we will get
[tex]M = \frac{d_i}{d_o}[/tex]
using the formula above we always get M < 1
which shows that image is smaller than the object and also since the image is always virtual so this is right side up
So the correct answer would be
4. Smaller and right side up