Question

Two number cubes are rolled.


What is the probability that the first lands on 2 and the second lands on a number greater than 4?

Answer 1

Well you need to find both probabilities first:

Landing on 2:

$\frac{1}{6}$

Landing on a number GREATER than 4:

$\frac{2}{6}$

Then multiply them together

$\frac{1}{6} * \frac{2}{6} = \frac{2}{36} = \frac{1}{18}$

So the probability of the two dice landing within those specific requirements is $\frac{1}{18}$

Hope this helps!