Question

If Lp is a diameter of circle m and , find NO.

Answer 1

Given that MP is the radius and bisector of QO, then:
QN=NO
hence:
4x-1=2x+3
solving for x
4x-2x=3+1
2x=4
x=2
thus
NO=2x+3=2(2)+3=7

Answer 2

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