rrelaxed2435 rrelaxed2435

16-05-2018
Chemistry

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In a second trial of this experiment, the molarity of koh(aq) was determined to be 0.95 m. the actual molarity was 0.83 m. what is the percent error in the second trial?

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kenmyna kenmyna

26-05-2018

The % error in the second trial is calculated as follows

% error = actual molarity/ theoretical molarity x100

= 0.83/0.95 x100 = 87.4% error of second trial

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