Question

In a second trial of this experiment, the molarity of koh(aq) was determined to be 0.95 m. the actual molarity was 0.83 m. what is the percent error in the second trial?

Answer 1

 The % error in the second trial  is calculated as follows

% error = actual molarity/  theoretical molarity  x100


= 0.83/0.95 x100 = 87.4% error of second trial