Question

Park rangers released 12 fish into a pond in year 0. Each year, there were twice as many fish as the year before. How many fish were there after x years? Write a function to represent this scenario.

Answer 1

y = 12 + 2x

This is probably right. I'm 99% sure. :)

Answer 2

Answer: The function would be,

$f(x)=12(2)^x$

Step-by-step explanation:

Given,

Park rangers released 12 fish into a pond in year 0,

Thus, the initial number of fish = 12,

Also, there were twice as many fish as the year before,

⇒ After 1 year the number of fishes = 2(12) = 12(2),

Similarly,

After 2 years = 2(12(2))= 12(2)²,

After 3 years = 2(12(2)²) = 12(2)³,

................, so on,....

Thus, the number of fishes after x years would be,

$12(2)^x$

Let f(x) represents the number of fish after x years,

$\implies f(x) = 12(2)^x$

Which is the required function that the given scenario.