Question

In ABC, what is the value of cos B?

Answer 1

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it is c
hope this helped

Answer 2

Answer:  The correct option is

(B) $\dfrac{12}{13}.$

Step-by-step explanation:  We are given to find the value of cos B in the right-angled triangle ABC shown.

From the figure, we can see that

AB = 12 units, BC = 13 units and AC = 5 units.

For the acute angle B, we have

base, b =  AB = 12 units

and

hypotenuse, h = BC = 13 units.

Therefore, we get

$\cos \angle B=\dfrac{base}{perpendicular}\\\\\\\Rightarrow \cos \angle B=\dfrac{AB}{BC}\\\\\\\Rightarrow \cos \angle B=\dfrac{12}{13}.$

Thus, option (B) is correct.