What mass of 95% pure CaCO3 will be required to neutralise 50 mL of 0.5 M HCl solution according to the following reaction? CaCO3(s)+ 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O [Calculate upto second place of decimal point] A. 1.32 g B. 3.65 g C. 9.50 g D. 1.25 g
