How many moles of BCl₃ are produced from the reaction of 61.0 grams of B₂O₃?

B₂O₃ (s) + 3C (s) + 3Cl₂ (g) → 2BCl₃ (g)

a. 0.0150 moles
b. 211 moles
c. 1.75 moles
d. 51.3 moles