The balanced equation of the redox reaction is given below as follows: Sn²⁺ (aq) + Cu(s) ----> Sn(s) + Cu²⁺ (aq) .
1. The reduction half-cell reaction would be: Cu⁺² +2e⁻ ⟶ Cu
2. The oxidation half-cell reaction would be: Sn2 ⟶ Sn⁺² + 2e⁻
3. The final equation would be: 2Cu⁺² + Sn⁺² ⟶ Sn⁺⁴ + 2Cu⁺
