Question

Solve the initial value problem(3+x2)y''+3y=0,y(0)=0,y'(0)=12.If the solution isy=c₀+c₁x+c₂x²+c₃x³+c₄x⁴+c₅x⁵+c₆x⁶+c₇x⁷+cdots,enter the following coefficients:
c₀=
c₁=
c₂=
c₃=
c₄=
c₅=
c₆=
c₇=