If 2.25 moles of BF3 is reacted wtih 4.37 moles of H2, which reactant is the limiting reactant according to the balanced reaction below? Using that limiting reactant what is the maximum amount of HF that can be produced in moles.
2 BF3 + 3 H2 2 B + 6 HF

a
H2, 8.73 moles of HF
b
BF3, 6.75 moles of HF
c
BF3, 13.10 moles of HF
d
H2, 4.50 moles of HF