If ( P(B | A) > P(B) ), show that ( P(B' | A) < P(B') ). [Hint: Add ( P(B' | A) ) to both sides of the given inequality and then use the fact that ( P(A | B) P(A' | B) = 1 ).]
a. ( P(A | B) < P(A) )
b. ( P(A' | B) > P(A') )
c. ( P(B' | A) > P(B) )
d. ( P(B | A') < P(B') )
