Question

Calculate the enthalpy change using the net ionic equation for the given neutralization reaction at 25°C: 2 KOH(aq) + H2SO4(aq) → K2SO4(aq) + H2O(l).
a) ΔH = -106.0 kJ
b) ΔH = -57.4 kJ
c) ΔH = -72.2 kJ
d) ΔH = -14.5 kJ