Given f(x)=4(x−2)3+2, classify each statement about f−1(x) as true or false. True False The point of symmetry on f−1(x) is (2,2). True – The point of symmetry on , f superscript negative 1 left parenthesis x right parenthesis, is , left parenthesis 2 comma 2 right parenthesis, . False – The point of symmetry on , f superscript negative 1 left parenthesis x right parenthesis, is , left parenthesis 2 comma 2 right parenthesis, . The domain of f−1(x) is (−∞,4). True – The domain of , f superscript negative 1 left parenthesis x right parenthesis, is , left parenthesis negative infinity comma 4 right parenthesis, . False – The domain of , f superscript negative 1 left parenthesis x right parenthesis, is , left parenthesis negative infinity comma 4 right parenthesis, . The graphs of f−1(x) and f(x) are reflections across the line y = x. True – The graphs of , f superscript negative 1 left parenthesis x right parenthesis, and , f left parenthesis x right parenthesis, are reflections across the line , y , = , x. False – The graphs of , f superscript negative 1 left parenthesis x right parenthesis, and , f left parenthesis x right parenthesis, are reflections across the line , y , = , x.  f−1(x) is not a function.