Using the Intermediate Value Theorem, show that the following equations have at least one solution in the given intervals:
2x cos(2x) - (x²) = 0 in [2, 3] and [3, 4].

a) 2x cos(2x) = x² in [2, 3] and [3, 4]
b) 2x cos(2x) = -x² in [2, 3] and [3, 4]
c) 2x cos(2x) = 0 in [2, 3] and [3, 4]
d) 2x cos(2x) = 2x² in [2, 3] and [3, 4]