A uniform meter ruler weighing 10 gF is pivoted at its O mark. What moment of force depresses the ruler? How can it be made horizontal by applying the least force? Calculate the force required.
a) 10 gF, by applying a force of 10 gF at the 1/2 mark
b) 5 gF, by applying a force of 5 gF at the 1/2 mark
c) 10 gF, by applying a force of 5 gF at the 1/2 mark
d) 5 gF, by applying a force of 10 gF at the 1/2 mark
