Consider the following inequality: 4≤x×3<7. Also, 2≤∣y×1∣<9. In step 4 of 5, using the two inequalities found in step 3, find the solution to the original inequality in both interval and algebraic notation.
a) 4≤x≤7; 2≤∣y∣<9
b) 1≤x≤3; 1≤∣y∣<4.5
c) 12≤x≤21; 0≤y<9
d) 0≤x≤7; 2≤y<9
