Assume (p)=0.40 in a sample size of n=100 . In addition, z₀.₀₂₅ =1.96 and t₀.₀₂₅,₉₉ =1.984 . A 95% confidence interval for the population proportion is
◯ 0.40+-1.984√((0.95(1-0.95))/(100))
◯ 0.40+-1.96√(100)
◯ 0.40+-1.984√((0.40(1-0.40))/(100))
◯ 0.40+-1.96√((0.95(1-0.95))/(100))
