Question

Let AB be any chord of the circle x² + y² – 2x – 6y – 6 = 0 which subtends right angle at the point (2, 4), then the locus of the mid point of AB is
(A) x² + y² – 3x – 7y –16 = 0
(B) x² + y² – 3x – 7y + 7 = 0
(C) x² + y² + 3x + 7y – 16 = 0
(D) x² + y² + 3x + 7y – 7 = 0