Calculate the volume (in mL) of 0.100 M CaCL2 needed to produce 1.00 g of Na2CO3(aq) + CaCL2(aq) → 2 NaCL(aq) + CaCO3(s). There is an excess of Na2CO3.
Molar mass of calcium carbonate = 100.09 g/mol
Volume of calcium chloride = _____mL
The answers 100, 10, and 0.1 are incorrect
