dwenger3422 dwenger3422
  • 30-01-2024
  • Computers and Technology
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Given the following code char a[] = {'c', 'a', 't', '\0'}; char *p = a; while (*p != 0) { *p = *p + 1; printf("%c", *(p++)); } What will happen?

1: The code will print "d"
2: The code will print "dau"
3: The code will print "cdu"
4 (Correct): The code will print "dbu"

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