Given a function, F(x)=∫x−23−4tdt
I'm having difficulty understanding why evaluating F(1) (equal to 15) is needed to supply the y-value of the tangent line. the tangent line apparently passes through (1,15) with a slope of −1, producing the equation x+y=16
the difficulty arises in interpreting what is happening visually at x=1. would graphing the antiderivative of 3−4t (3t−2t2+c) be of any help?
